If an aqueous solution is 1.54 % by weight in sodium chloride and contains 6.96 g of sodium chloride, what mass of water is present in the solution?
200g
To find the mass of water present in the solution, we need to subtract the mass of sodium chloride from the total mass of the solution.
1. First, let's calculate the total mass of the solution. The solution is 1.54% by weight in sodium chloride, which means the remaining 98.46% is water. Since percentages are based on a 100 g total, we can calculate the total mass of the solution using the equation:
Total mass of solution = Mass of sodium chloride / Percentage of sodium chloride
Total mass of solution = 6.96 g / 1.54% = 451.95 g (rounded to two decimal places)
2. Next, we can find the mass of water in the solution by subtracting the mass of sodium chloride from the total mass of the solution:
Mass of water = Total mass of solution - Mass of sodium chloride
Mass of water = 451.95 g - 6.96 g = 444.99 g (rounded to two decimal places)
Therefore, the mass of water present in the solution is approximately 444.99 g.
If a solution is 1.54% w/w then for 100 g of solution 1.54 g of the soluton is NaCl and the other 98.46 g is water.
If we have 2 x 1.54 g of NaCl we must have 2 x 98.46 g of water.
So if we have 6.96 g of NaCl how much water?