A 47 N box is pulled along a frictionless horizontal surface by a 25 N weight hanging from a cord on a frictionless pulley? What is the acceleration of the system (box and the weight)?

The acceleration of the system is 1.88 m/s^2. This can be calculated using the equation a = F/m, where F is the net force and m is the total mass of the system. The net force is the difference between the 47 N box and the 25 N weight, which is 22 N. The total mass of the system is the mass of the box plus the mass of the weight, which is 72 N. Therefore, a = 22 N/72 N = 1.88 m/s^2.

To find the acceleration of the system, we need to calculate the net force acting on the system. The net force is equal to the difference between the force applied by the hanging weight and the force of friction.

Given:
Force applied by the hanging weight (F1) = 25 N
Force of friction (Ffriction) = 0 N (frictionless surface)

Net force (Fnet) = F1 - Ffriction

Since Ffriction = 0 N, the net force is simply the force applied by the hanging weight.

Fnet = F1
= 25 N

Next, we can use Newton's second law of motion to relate the net force and acceleration:

Fnet = m * a

Where:
m = mass of the system
a = acceleration of the system

Rearranging the equation to solve for acceleration:
a = Fnet / m

To solve for the mass of the system, we need to use the formula:
Weight = mass * acceleration due to gravity (g)

Given:
Weight of the box (F2) = 47 N (since the box is on a frictionless surface, its weight is acting downward)

Rearranging the formula:
mass = weight / acceleration due to gravity

Let's assume the acceleration due to gravity (g) is 9.8 m/s^2.

mass of the box (m) = F2 / g
= 47 N / 9.8 m/s^2
≈ 4.8 kg

Now, substituting the values into the equation for acceleration:
a = Fnet / m
= 25 N / 4.8 kg
≈ 5.21 m/s^2

Therefore, the acceleration of the system (box and weight) is approximately 5.21 m/s^2.

To find the acceleration of the system (box and weight), we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.

First, let's calculate the net force acting on the system. In this case, the only force acting on the system is the weight of the hanging mass, which is 25 N. Since there is no friction, there are no other forces to consider.

Next, we need to determine the combined mass of the box and the weight. Let's assume the mass of the box is m1, and the mass of the weight is m2. Since the weight is hanging vertically, we can use the formula: weight = mass × acceleration due to gravity (which is approximately 9.8 m/s^2).

From the given information, we know the weight of the hanging mass is 25 N. Rearranging the formula, we can find the mass of the weight:

mass of the weight (m2) = weight / acceleration due to gravity = 25 N / 9.8 m/s^2

Now, we can sum up the masses of the box and the weight to find the total mass (m) of the system:

total mass (m) = m1 + m2

Finally, we can calculate the acceleration (a) of the system using Newton's second law:

acceleration (a) = net force / total mass

In this case, the net force is equal to the weight of the hanging mass (25 N), and the total mass is the sum of the box's mass and the weight's mass.

So the equation becomes:

acceleration (a) = 25 N / (m1 + m2)

To determine the acceleration of the system, you need to know the mass of the box (m1). If the mass of the box is given, substitute it into the formula to find the acceleration.