In an emergency stop to avoid an accident,a shoulderstrap seat belt holds a 60-kg passenger firmly in place. If the car were initally traveling at 90 km/h and came to a stop in 5.5s along a straight, level road, what was the average force applied to the passenger by the seatbelt?

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  1. First convert 90 km/h to ___meters per second.
    The conversion factor is
    (1000 m/km) * (1 hr/3600s)
    Divide that speed in m/s by 5.5 s to get the deceleration rate in m/s^2.

    Mass(kg) x acceleration (m/s^2)
    = Force (Newtons)

    If you want it in pounds, multiply Newtons by 0.225 lb/N

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  2. 272.7

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