the legs of an isosceles triangle have lengths 2x+4 and x-8 the base has length 5x-2 whats the lenght of base
since the triangle is isosceles, we know that the legs have the same length:
2x+4 = x-8
x=-12
base = 5x-2 = -62
what's wrong with this picture?
To find the length of the base of the isosceles triangle, we need to compare the lengths of the legs and the base.
Given:
Leg 1 = 2x + 4
Leg 2 = x - 8
Base = 5x - 2
Since it's an isosceles triangle, the lengths of the legs are equal. We can set Leg 1 equal to Leg 2 and solve for x.
2x + 4 = x - 8
To solve this equation, we need to isolate the variable "x". We can start by moving all the terms with the variable "x" to one side of the equation.
2x - x = -8 - 4
x = -12
Now that we have the value of "x", we can substitute it back into the equation for the base length:
Base = 5(-12) - 2
Base = -60 - 2
Base = -62
Therefore, the length of the base of the isosceles triangle is -62.