cold water
mass of calimeter+ water: 68.66g
mass of calimeter: 19.19g
mass of water: 49.47g
final temperature of water: 39.1C
initial temperature of water: 25.5C
delta(T) of water: 13.6C
hot water
mass of calimeter+ water: 79.55g
mass of calimeter: 20.61g
mass of water: 58.94g
final temperature of water: 39.1C
initial temperature of water: 52.2C
delta(T) of water: -13.1C
calulate the q-hotwater (specific heat of water 4.18J g^-1 C^-1)
calculate the q-coldwater
can someone please explain to me how this question is done? thanks =]
q for hot water = mass H2O x specific heat H2O x (Tfinal-Tinitial).
q for cold water = mass H2O x specific heat H2O x (Tfinal-Tinitial).
To calculate the heat transfer (q) for the hot water and cold water, we will use the formula:
q = m * c * ΔT
Where:
- q is the heat transfer
- m is the mass of the substance
- c is the specific heat capacity of the substance
- ΔT is the change in temperature
Let's start with the hot water:
1. Calculate q-hotwater:
Given:
Mass of hot water (m) = 58.94 g
Change in temperature (ΔT) = -13.1 °C
Specific heat capacity of water (c) = 4.18 J g^(-1) °C^(-1)
To find q-hotwater, substitute the values into the formula:
q-hotwater = 58.94 g * 4.18 J g^(-1) °C^(-1) * (-13.1 °C)
Now, calculate the result.
Next, let's calculate the q-coldwater:
2. Calculate q-coldwater:
Given:
Mass of cold water (m) = 49.47 g
Change in temperature (ΔT) = 13.6 °C
Specific heat capacity of water (c) = 4.18 J g^(-1) °C^(-1)
To find q-coldwater, substitute the values into the formula:
q-coldwater = 49.47 g * 4.18 J g^(-1) °C^(-1) * 13.6 °C
Now, calculate the result.
Please perform these calculations to find the values for q-hotwater and q-coldwater. Let me know if you need further assistance.