An object is on a frictionless inclined plane. The plane is inclined at an angle of 16.9 degrees with the horizontal. Using the accerlation due gravity(9.8m/s squared),what is the magnitude of object's acceleration?
YO are you vlad from my geometry class, mr. schwaigoffer
9.8m/s
good question
To find the magnitude of the object's acceleration on the frictionless inclined plane, you can use the following equation:
a = g * sin(theta)
Where:
a = acceleration
g = acceleration due to gravity (9.8 m/s^2)
theta = angle of inclination (16.9 degrees)
First, convert the angle from degrees to radians (since trigonometric functions require radians):
theta_radians = theta * (pi/180)
theta_radians = 16.9 * (pi/180)
theta_radians ≈ 0.294524 rad
Next, substitute the values into the equation:
a = 9.8 * sin(theta_radians)
a ≈ 9.8 * sin(0.294524)
a ≈ 9.8 * 0.288675
a ≈ 2.843 m/s^2
Therefore, the magnitude of the object's acceleration on the frictionless inclined plane is approximately 2.843 m/s^2.