Calculus

for the function F(t)=ln(t^2), let f(t)=F'(t). Write the integral from a to b of f(t) dt and evaluate it with the fundamental theorem of calculus.

the integral from 1 to 3 ___ dt= __

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  1. F(t) = ln t^2
    = 2 lnt

    f(t) = 2/t

    so if you want ∫f(t) dt from 1 to 3
    = ln t^2 from 1 to 3
    = ln9 - ln1
    = ln9 - 0
    = ln 9

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