In a European country a bathroom scale displays its reading in kilograms. When a man stands on this scale, it reads 90.4 kg. When he pulls down on a chin-up bar installed over the scale, the reading decreases to 79.5 kg. What is the magnitude of the force he exerts on the chin-up bar?
9.8 (90.4-79.5) Newtons
The magnitud of the force is 1.14
To find the magnitude of the force the man exerts on the chin-up bar, we can use Newton's second law of motion, which states that force (F) is equal to the mass (m) multiplied by the acceleration (a) produced:
F = m * a
In this case, the mass of the man remains constant, so the acceleration produced is equal to the difference in readings on the scale:
a = (90.4 kg - 79.5 kg)
Simplifying that, we get:
a = 10.9 kg
Now, we need to determine the force exerted. Force (F) is equal to mass (m) multiplied by acceleration (a). Rearranging the formula, we have:
F = m * a
F = 79.5 kg * 10.9 kg
F = 866.55 N
Therefore, the magnitude of the force he exerts on the chin-up bar is approximately 866.55 Newtons.
To determine the magnitude of the force exerted on the chin-up bar, we need to consider the change in weight due to the force applied.
1. Start by converting the readings on the scale from kilograms to Newtons. The conversion factor is 1 kg = 9.8 N (acceleration due to gravity).
The initial reading on the scale is 90.4 kg, which is equivalent to:
90.4 kg x 9.8 N/kg = 886.72 N
The reading on the scale when he pulls down on the chin-up bar is 79.5 kg, which is equivalent to:
79.5 kg x 9.8 N/kg = 779.1 N
2. Calculate the change in weight by subtracting the weight when pulling down on the chin-up bar from the initial weight:
Change in weight = Initial weight - Weight when pulling down
Change in weight = 886.72 N - 779.1 N = 107.62 N
The magnitude of the force exerted on the chin-up bar is equal to the change in weight, which is 107.62 N.