divisible by 15,27,36,16,28,57,102,268,4518,93
en.wikipedia.org/wiki/List_of_prime_n
umbers
15 = 3*5
27 = 3*3*3
36 = 2*2*3*3
16 = 2*2*2*2
28 = 2*2*7
57 = 3*19
102 = 2*51
268 = 2*2*67
4518=2*2259 = 2*3*753 = 2*3*3*251
93 = 3*31
2^4 * 3^3 * 7 * 19 * 51 * 67 * 251 * 31
whoops
102 = 2*51 = 2*3*17
15 = 3*5
27 = 3*3*3
36 = 2*2*3*3
16 = 2*2*2*2
28 = 2*2*7
57 = 3*19
102 = 2*51= 2*3*17
268 = 2*2*67
4518=2*2259 = 2*3*753 = 2*3*3*251
93 = 3*31
so
2^4 * 3^3 * 7 * 19 * 17 * 67 * 251 * 31
about 5.09 * 10^11
To find a number that is divisible by a given set of numbers, you need to find the least common multiple (LCM) of those numbers. The LCM is the smallest number that is a multiple of all the given numbers.
To calculate the LCM, you can follow these steps:
1. Prime factorize all the numbers in the given set.
- 15 = 3 × 5
- 27 = 3^3
- 36 = 2^2 × 3^2
- 16 = 2^4
- 28 = 2^2 × 7
- 57 = 3 × 19
- 102 = 2 × 3 × 17
- 268 = 2^2 × 67
- 4518 = 2 × 3^4 × 7
- 93 = 3 × 31
2. Identify the highest power of each prime factor from all the factorizations.
- Prime factor 2: 2^4
- Prime factor 3: 3^4
- Prime factor 5: 5^1
- Prime factor 7: 7^1
- Prime factor 19: 19^1
- Prime factor 17: 17^1
- Prime factor 67: 67^1
- Prime factor 31: 31^1
3. Multiply all the prime factors raised to their highest powers.
LCM = 2^4 × 3^4 × 5^1 × 7^1 × 19^1 × 17^1 × 67^1 × 31^1
Now, you can simplify this expression to find the LCM.
LCM = 2^4 × 3^4 × 5 × 7 × 19 × 17 × 67 × 31
Simplifying this expression results in a very large number:
LCM = 3,297,389,520
So, the number that is divisible by 15, 27, 36, 16, 28, 57, 102, 268, 4518, and 93 is 3,297,389,520.