5. The industrial production of hydroiodic acid takes place by treatment of iodine with hydrazine (N2H4):
2I2 + N2H4 → 4HI + N2
a.How many grams of I2 are needed to react with 36.7 g of N2H4
Here is a worked example of a stoichiometry problem. Just follow the steps. http://www.jiskha.com/science/chemistry/stoichiometry.html
To find out how many grams of I2 are needed to react with 36.7 g of N2H4, we need to use the balanced chemical equation and calculate the stoichiometry of the reaction.
First, let's calculate the molar mass of N2H4 and I2:
Molar mass of N2H4:
2(14.01) + 4(1.01) = 32.05 g/mol
Molar mass of I2:
2(126.9) = 253.8 g/mol
Next, we can set up a conversion using the balanced chemical equation:
2I2 + N2H4 → 4HI + N2
From the balanced equation, we can see that 2 moles of I2 react with 1 mole of N2H4. We can use this ratio to convert grams of N2H4 to moles, then moles to grams of I2.
1. Convert grams of N2H4 to moles:
36.7 g N2H4 * (1 mol N2H4 / 32.05 g N2H4) = 1.145 mol N2H4
2. Use the mole ratio from the balanced equation to find moles of I2:
1.145 mol N2H4 * (2 mol I2 / 1 mol N2H4) = 2.29 mol I2
3. Convert moles of I2 to grams:
2.29 mol I2 * (253.8 g I2 / 1 mol I2) = 581.8 g I2
Therefore, 581.8 grams of I2 are needed to react with 36.7 grams of N2H4.
To determine the number of grams of I2 needed to react with 36.7 g of N2H4, we'll use the balanced chemical equation provided.
The molar mass of N2H4 is 32.05 g/mol.
The molar mass of I2 is 253.8 g/mol.
We can use the molar ratios in the balanced equation to convert the mass of N2H4 to the moles of I2.
1 mole of N2H4 reacts with 2 moles of I2.
First, let's convert the mass of N2H4 to moles:
36.7 g N2H4 * (1 mol N2H4 / 32.05 g N2H4) = 1.146 mol N2H4
Now, we use the molar ratio from the balanced equation to find the moles of I2:
1.146 mol N2H4 * (2 mol I2 / 1 mol N2H4) = 2.292 mol I2
Finally, we convert the moles of I2 to grams:
2.292 mol I2 * (253.8 g I2 / 1 mol I2) = 581.8 g I2
Therefore, approximately 581.8 grams of I2 are needed to react with 36.7 grams of N2H4.