solve v^2+v-6=0
Would v=2
is 2^2 + 2 - 6 = 0 ?
v^2 + v - 6= 0
(v-2)(v+3) = 0
so v = ? or v = ?
V=2 v=-3
correct
Thank You
To solve the quadratic equation v^2 + v - 6 = 0, you can use the quadratic formula:
v = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 1, b = 1, and c = -6.
Substituting these values into the formula:
v = (-(1) ± √((1)^2 - 4(1)(-6))) / (2(1))
v = (-1 ± √(1 + 24)) / 2
v = (-1 ± √25) / 2
Simplifying further:
v = (-1 ± 5) / 2
We have two solutions:
v1 = (-1 + 5) / 2 = 4 / 2 = 2
v2 = (-1 - 5) / 2 = -6 / 2 = -3
So, the solutions to the equation v^2 + v - 6 = 0 are v = 2 and v = -3.