solve v^2+v-6=0

Would v=2

is 2^2 + 2 - 6 = 0 ?

v^2 + v - 6= 0
(v-2)(v+3) = 0
so v = ? or v = ?

V=2 v=-3

correct

Thank You

To solve the quadratic equation v^2 + v - 6 = 0, you can use the quadratic formula:

v = (-b ± √(b^2 - 4ac)) / (2a)

In this equation, a = 1, b = 1, and c = -6.

Substituting these values into the formula:

v = (-(1) ± √((1)^2 - 4(1)(-6))) / (2(1))
v = (-1 ± √(1 + 24)) / 2
v = (-1 ± √25) / 2

Simplifying further:

v = (-1 ± 5) / 2

We have two solutions:

v1 = (-1 + 5) / 2 = 4 / 2 = 2
v2 = (-1 - 5) / 2 = -6 / 2 = -3

So, the solutions to the equation v^2 + v - 6 = 0 are v = 2 and v = -3.