eight pairs of data yield the regression equation y^1=55.8+2.79x. What is the value of y for x=5.6?
y^1 ? , why not just y ?
y = 55.8 + 2.79(5.6)
I will let you do the button-pushing
I don't understand why everyone answers this problem by solving for x like that is not the most obvious thing in the world. No one needs help solving for x. I need help understanding when you use the y mean and when you solve fo x and use that....
To find the value of y for x=5.6 using the given regression equation y^1=55.8+2.79x, we can substitute x=5.6 into the equation and solve for y.
Substituting x=5.6 into the equation:
y^1 = 55.8 + 2.79(5.6)
Calculating:
y^1 = 55.8 + 15.624
y^1 = 71.424
Therefore, the value of y for x=5.6 is approximately 71.424.
To find the value of y for a given x using the regression equation, you can simply substitute the given value of x into the equation and solve for y.
Given regression equation: y^1 = 55.8 + 2.79x
Substituting x = 5.6 into the equation:
y^1 = 55.8 + 2.79(5.6)
Now, let's calculate the value of y:
y^1 = 55.8 + 15.624
Adding the numbers:
y^1 = 71.424
Therefore, the value of y when x = 5.6 is approximately 71.424.