Questions LLC
Login
or
Sign Up
Ask a New Question
Questions
Math
a freight train leaves detroit traveling east at a speed of 65mph. one hour later, a passanger train leaves traveling wst a 85mph. how long will it take for the trains to have traveled the sam distance?
1 answer
65 t = 85(t-1)
You can
ask a new question
or
answer this question
.
Similar Questions
Is there an easier way to do this? "A freight train leaves a station at 4:00 p.m. traveling at 30 kilometers per hour. A
Top answer:
An easier way than what? In these kind of problems you have to find which of the three variables,
Read more.
A freight train leaves Chicago traveling West at 35 mph. An hour later a passenger train leaves Chicago traveling on a parallel
Top answer:
let the distance traveled when the second catches up be x miles time for the freight train to go x
Read more.
A freight train leaves St. Louis traveling at 85 km/hr.
One hour later, a passenger train leaves St. Louis on a parallel track
Top answer:
a) The equation we would use to find the time spent by the first train traveling is h=x/v, where x
Read more.
5) A freight train leaves a station traveling at 32 km/h. Two hours later, a passenger train leaves
the same station traveling in
Top answer:
the distance traveled is the same distancefirst=32*time distancesecond=52*(time-2) set them equal,
Read more.
A freight train leaves St. Louis traveling at 70km/hr.
One hour later, a passenger train leaves St. Louis on a parallel track
Top answer:
a) The equation to find the time spent traveling by the first train can be written as: Distance =
Read more.
A freight train leaves a station traveling at 32 km/h. Two hours later, a passenger train leaves
the same station traveling in
Top answer:
32 (t + 2)= d 52 t = d so 32 t + 64 = 52 t 20 t = 64 t = 3.2 hours and 12 minutes
Read more.
A freight train leaves St. Louis traveling at 85 km/hr.
One hour later, a passenger train leaves St. Louis on a parallel track
Top answer:
a) The equation to find the time the first train spends traveling can be written as: 85(h+1) = 105h,
Read more.
A freight train leaves St. Louis traveling at 85 km/hr.
One hour later, a passenger train leaves St. Louis on a parallel track
Top answer:
To find the time the first train spends traveling, we can use the equation: distance = speed × time
Read more.
A freight train leaves St. Louis traveling at 80 km/hr.
One hour later, a passenger train leaves St. Louis on a parallel track
Top answer:
a) The equation that would be used to find the time the first train spends traveling can be written
Read more.
A freight train leaves St. Louis traveling at 80 km/hr.
One hour later, a passenger train leaves St. Louis on a parallel track
Top answer:
a) The equation we would use to find the time spent traveling by the first train is: Distance =
Read more.
Related Questions
A cargo train and a passenger train, which start from two stations that are 710 km apart, are traveling towards each other. The
2. A freight train traveling with a velocity of 18.0 m/s to the south begins braking as it approaches the train yard. The
An engineer of a passenger train traveling at 25.0 m/s sights a freight train whose caboose is 200m ahead on the same track. The
A train leaves New York at 1:00 PM. A second train leaves the same city in the same direction at 3:00 PM. The second train
A freight train leaves St. Louis traveling at 70 km/hr.
One hour later, a passenger train leaves St. Louis on a parallel track
A passenger train is traveling at 30 m/s when the engineer sees a freight train 357 m ahead of his train traveling in the same
A passenger train is traveling at 27 m/s when the engineer sees a freight train 345 m ahead of his train traveling in the same
A freight train leaves at 1:00 PM from a station. A passenger train leaves at 3:00 PM from the same station and travels in the
a passenger train traveling at 50 mph leaves the station 6 hours after a freight train and ovetakes it in 4 hours . How fast is
A train leaves the station at 9:00 pm traveling east at 36 miles per hour. A second train leaves the station at 10:00 pm