calculus

find f(x -1) for the following function
f(x) = sqrtx^2 - 3/ 6x + 6

asked by amy
  1. Is the entire equation underneath the square root or just the numerator? If it is just the numerator then here is the answer:

    [sqrt((x-1)(x-1)-3)]/[6(x-1)+6]
    [sqrt(x^2 -2x+1-3)]/[6x-6+6]
    [sqrt(x^2 -2x-2)]/6x
    [sqrt(x-1)^2]/6x
    x-1/6x

    I added brackets to make it easier to distinguish between numerator and denominator. If the whole equation was underneath the square root then the answer would be:

    sqrt((x-1)^2)/6x

    posted by michael

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