You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 2.070E+7 m and its rotation to be 19.8 hours. You have previously determined that the planet orbits 1.590E+11 m from its star with a period of 368.0 Earth days. Once on the surface you find that the free-fall acceleration is 13.00 m/s2.

What is the mass of the star (in kg)?

Please read and apply my previous answer. See "related questions" below.

I did that and it still did not come out correctly.

To find the mass of the star, we can use the laws of gravitation and the given information.

The formula for finding the mass of a celestial body is:

M = (4 * π² * R³) / (G * T²)

Where M is the mass of the celestial body, R is the distance from the center of the celestial body to the planet's orbit, G is the gravitational constant (6.67430 × 10^-11 N m²/kg²), and T is the orbital period of the planet.

First, let's convert the given values into SI units:
R = 1.590E+11 m
T = 368.0 Earth days = 368.0 * 24 * 3600 seconds

Now we can substitute these values into the formula:

M = (4 * π² * (1.590E+11)³) / (6.67430 × 10^-11 * (368.0 * 24 * 3600)²)

Calculating the right side of the equation will give us the mass of the celestial body, which is the star in this case.

M ≈ 8.79 × 10^29 kg

Therefore, the mass of the star is approximately 8.79 × 10^29 kg.