How many moles of sulfate ions are present in 1.2 mol of aluminum sulfate?
Aluminum sulfate is Al2(SO4)3. There are 3 moles of SO4^2- in each mole of Al2(SO4)3.
To find the number of moles of sulfate ions in 1.2 moles of aluminum sulfate, we need to determine the mole ratio between sulfate ions and aluminum sulfate.
The chemical formula for aluminum sulfate is Al2(SO4)3, which indicates that for every 1 mole of aluminum sulfate, there are 3 moles of sulfate ions.
Therefore, to find the number of moles of sulfate ions in 1.2 moles of aluminum sulfate, we can multiply the given moles of aluminum sulfate by the mole ratio:
Number of moles of sulfate ions = 1.2 moles of aluminum sulfate x (3 moles of sulfate ions / 1 mole of aluminum sulfate)
Number of moles of sulfate ions = 1.2 moles of aluminum sulfate x 3
Number of moles of sulfate ions = 3.6 moles
Therefore, there are 3.6 moles of sulfate ions present in 1.2 moles of aluminum sulfate.
To determine the number of moles of sulfate ions present in 1.2 moles of aluminum sulfate, we need to know the chemical formula of aluminum sulfate and its molar ratio with respect to sulfate ions.
The chemical formula of aluminum sulfate is Al2(SO4)3. This means that for every 1 mole of aluminum sulfate, there are 3 moles of sulfate ions.
Since we have 1.2 moles of aluminum sulfate, we can calculate the number of moles of sulfate ions as follows:
1.2 moles aluminum sulfate x (3 moles sulfate ions / 1 mole aluminum sulfate) = 3.6 moles sulfate ions
Therefore, there are 3.6 moles of sulfate ions present in 1.2 moles of aluminum sulfate.