how do i complete and balnces theses reactions????
CH3-CH2-CH3 (g) + Br2 (l) -->
like how in the world????? do i do this?
lol aint got a clue wish i would have listened at school now.
Alkanes usually react with a halogen to form one of several halides. The simplest reaction is to add one atom of Br on the end of the reaction. That is, the end H reacts with one atom of Br to form HBr and the other atom of Br adds to the spot vacated by the H atom.
CH3CH2CH3 + Br2 ==> HBr + CH3CH2CH2Br.
In practice and under various conditions, additional Br atoms may add to the other spots held by H atoms. I hope this helps.
To complete and balance the reaction CH3-CH2-CH3 (g) + Br2 (l) -->, you need to follow a few steps. Here's a breakdown of the process:
Step 1: Write the unbalanced equation:
CH3-CH2-CH3 (g) + Br2 (l) -->
Step 2: Count the number of atoms on both sides of the equation. In this case, we have 3 carbon (C) atoms and 8 hydrogen (H) atoms on the left side, and 3 carbon (C) atoms, 8 hydrogen (H) atoms, and 2 bromine (Br) atoms on the right side.
Step 3: Start by balancing the carbon (C) atoms. Since there are 3 carbon atoms on both sides, this step is already balanced.
Step 4: Next, balance the hydrogen (H) atoms. Since there are 8 hydrogen atoms on both sides, this step is also balanced.
Step 5: Finally, balance the bromine (Br) atoms. Since there are 2 bromine atoms on the right side, we need to balance it on the left side as well. To do this, we add a coefficient of 2 in front of the CH3CH2CH3 compound:
2CH3CH2CH3 (g) + Br2 (l) -->
Now, the equation is balanced with 2 carbon (C) atoms, 8 hydrogen (H) atoms, and 2 bromine (Br) atoms on both sides.
The balanced equation is:
2CH3CH2CH3 (g) + Br2 (l) --> 2CH3CH2CH2Br (g) + HBr (g)
Remember, when balancing chemical equations, the goal is to have the same number of each type of atom on both sides. By following these steps, you can balance the reaction equation.