how long does a car with an acceleration of 2.0 m/s^2 take to go from 10m/s to 30m/s?and its solution
if that is constant acceleration,
a = (v-u)/t
plug inthe numbers and you get the time elapsed.
To find the time it takes for the car to go from 10 m/s to 30 m/s with an acceleration of 2.0 m/s^2, we can use the following formula:
v = u + at
Where:
v = final velocity (30 m/s)
u = initial velocity (10 m/s)
a = acceleration (2.0 m/s^2)
t = time
Rearranging the formula to solve for time (t):
t = (v - u) / a
Substituting the given values:
t = (30 m/s - 10 m/s) / 2.0 m/s^2
t = 20 m/s / 2.0 m/s^2
t = 10 s
So, it takes the car 10 seconds to go from 10 m/s to 30 m/s with an acceleration of 2.0 m/s^2.
GIVEN:
Vf=30m/s
Vi=10m/s
a=.0m/s^2
REQUIRED:
t=?
SOLUTION
t=(Vf-Vi)/a
=(30m/s-10m/s)/2.0m/s^2
t=10s