Nitrogen monoxide + Hydrogen --> nitrogen + water

I need to balance this equation but I do not know how.

NO + H --> N + H2O

2NO + 2H --> 2N Would this be correct?

Thank you!!

Those aren't correct. One reason you have trouble is that you have failed to note that some of the molecules occurs as diatomic molecules. For example, you should write

NO + H2 ==> N2 + H2O
Now see if you can balance it. It should be easier now.

To balance the equation, you need to make sure that there are the same number of atoms on both sides of the equation. Here's how you can balance the given equation:

1. First, equalize the number of nitrogen (N) atoms on both sides of the equation. In this case, we have one nitrogen atom on the left side, but we need two nitrogen atoms on the right side. So, we multiply the nitrogen molecule (N₂) on the right side by 2.

NO + H₂ → 2N + H₂O

2NO + 2H₂ → 2N + 2H₂O

2. Now, let's balance the oxygen (O) atoms. On the left side, we have 2 oxygen atoms from the nitric oxide (NO) molecule. To match this number on the right side, we need to multiply the water (H₂O) molecule by 2.

2NO + 2H₂ → 2N + 2H₂O

3. Afterwards, we check if the hydrogen (H) atoms are balanced. We can see that there are 4 hydrogen atoms on the left side, but only 2 hydrogen atoms on the right side. To fix this, we need to multiply the hydrogen molecule (H₂) on the right side by 2.

2NO + 2H₂ → 2N + 4H₂O

Now, the equation is balanced. Each element has an equal number of atoms on both sides. Here's the balanced equation:

2NO + 2H₂ → 2N + 4H₂O