Find the area in the first quadrant bounded by the arc of the circle described by the polar equation
r = (2 sin theta)+(4 cos theta)

A. 5pi/2
B. (5pi/2)+4
C. 5pi
D. 5pi + 8

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asked by Tracy
  1. Recall that in polar coordinates,

    A = Int(1/2 r^2 dθ)

    r^2 = 4 sin^2θ + 8sinθcosθ + 16cos^2θ
    = 4 + 4sin2θ + 12cos^2θ
    = 10 + 4sin2θ + 6cos2θ

    A = Int(5 + 2sin2θ + 3cos2θ)dθ [0,pi/2]
    = 5t - cos2θ + 3/2 sin2θ [0,pi/2]
    = [5pi/2 + 1 + 0] - [0 - 1 + 0]
    = 5pi/2 + 2

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    posted by Steve

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