I'm at LIM x->0 e^x+cosx / e^x +sinx but now I at a lost as to how to proceed.
e^x + cosx --> 1 + 1 = 2 e^x + sinx --> 1 + 0 = 1 answer: 2/1 = 2 You only need L'Hospital's Rule when you wind up with 0/0 or ∞/∞ Unless the problem has a typo . . .
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