a woman age and her son added to 45, 5 years ago the woman was 6 times as old as her son. how old was the woman when the son was born.
w+s = 45
(w-5) = 6(s-5)
w - 5 = 6 s - 30
or
w - 6s = -25
w + 1s = 45
------------
-7 s = - 70
s = 10
then
w = 35
difference w-s = 25 years older
follow the same steps as I just showed you in the previous post.
Let me know what you got.
Thanks I am grateful
the woman was 25 years when son was born
To solve this problem, we need to set up equations based on the given information and use algebra to find the solution.
Let's denote the current age of the woman as "W" and the current age of the son as "S."
According to the first piece of information, the sum of their ages is 45: W + S = 45.
Now, let's consider the second piece of information given. Five years ago, the woman was 6 times as old as her son. This can be represented algebraically as: W - 5 = 6(S - 5).
Now we have a system of two equations that we can solve simultaneously.
1. W + S = 45
2. W - 5 = 6(S - 5)
To solve this system, we can use the method of substitution or elimination. Let's use the substitution method as an example:
From equation 1, we can isolate one variable:
W = 45 - S
Now substitute this expression for W in equation 2:
(45 - S) - 5 = 6(S - 5)
Simplify the equation:
40 - S = 6S - 30
Add S to both sides:
40 = 7S - 30
Add 30 to both sides:
70 = 7S
Divide by 7:
S = 10
Now, we can substitute the value of S back into either equation to find W:
W + 10 = 45
W = 35
So, the current age of the woman is 35, and the current age of the son is 10.
To find out how old the woman was when the son was born, we need to subtract the son's age from the woman's age. The woman is now 35, and the son is now 10, which means the woman was 25 years old when the son was born.