bisi and ada age added up to 29, 7 years ago bisi was twice as old as ada, find their present age.
bisi now -- x
ada now -- 29-x
7 yrs ago:
bisi -- x-7
ada -- 29-x - 7 = 22-x
x-7 = 2(22-x)
x-7 = 44 - 2x
3x = 51
x = 17
bisi is now 17
ada is now 12
check:
7 years ago: bisi was 10, ada was 5
Was bisi twice as old as ada ?? YES
To solve this problem, let's assign variables to Bisi's and Ada's present ages. Let's say Bisi's age is represented by "x" and Ada's age is represented by "y".
According to the information given, we know that the sum of their ages is 29. So, we can write the equation:
x + y = 29
We also know that 7 years ago, Bisi was twice as old as Ada. We can express this as another equation:
(x - 7) = 2(y - 7)
Now, we have a system of two equations. We can solve this system to find the values of x and y.
Let's start by solving the first equation for y:
y = 29 - x
Substitute this value of y into the second equation:
(x - 7) = 2(29 - x - 7)
Simplify the equation:
x - 7 = 58 - 2x - 14
Combine like terms:
3x - 7 = 58 - 14
3x - 7 = 44
Add 7 to both sides:
3x = 51
Divide both sides by 3:
x = 17
Now, substitute the value of x into the first equation to find the value of y:
17 + y = 29
y = 29 - 17
y = 12
Therefore, Bisi's present age is 17 and Ada's present age is 12.