An object wuth a mass of .5 kg starts from rest and achieves a maximum speed of 20m/s in 0.01 s. What average unbalanced force accelerates this object?
To find the average unbalanced force that accelerates the object, we can use Newton's second law of motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a). In this case, we need to find the acceleration of the object.
First, we can calculate the acceleration of the object using the formula:
acceleration (a) = change in velocity / time taken
Given that the object starts from rest (initial velocity = 0 m/s) and achieves a maximum speed of 20 m/s in 0.01 s, we can calculate the change in velocity:
change in velocity = final velocity - initial velocity
= 20 m/s - 0 m/s
= 20 m/s
Now, we can calculate the acceleration:
acceleration (a) = change in velocity / time taken
= 20 m/s / 0.01 s
= 2000 m/s²
Now that we have the acceleration, we can find the average unbalanced force using Newton's second law of motion:
force (F) = mass (m) * acceleration (a)
Given that the mass of the object is 0.5 kg, we can calculate the average unbalanced force:
force (F) = 0.5 kg * 2000 m/s²
= 1000 N
Therefore, the average unbalanced force that accelerates this object is 1000 N.
To find the average unbalanced force that accelerates the object, we can use Newton's second law of motion: F = ma, where F is the force, m is the mass, and a is the acceleration.
First, let's find the acceleration of the object:
Using the equation v = u + at, where v is the final velocity, u is the initial velocity (zero in this case), and t is the time, we can rearrange the equation to solve for acceleration:
v = u + at
20 m/s = 0 + a(0.01 s)
Rearranging the equation, we get:
a = (20 m/s) / (0.01 s) = 2000 m/s²
Now that we have the acceleration, we can calculate the force:
F = ma
F = (0.5 kg)(2000 m/s²)
F = 1000 N
Therefore, the average unbalanced force that accelerates this object is 1000 Newtons.
force= mass*acceleration
where acceleration =20/.01 m/s^2