what mass of SO2 is formed upon the complete combustion of 1.59g of methanethiol
Just follow the steps in this worked example.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the mass of SO2 formed upon the complete combustion of methanethiol (CH3SH), we first need to write and balance the chemical equation for the reaction.
The combustion of methanethiol can be represented by the following balanced chemical equation:
2 CH3SH + 3 O2 -> 2 SO2 + 4 H2O
From the balanced equation, we can see that for every 2 moles of CH3SH combusted, we get 2 moles of SO2.
Step 1: Calculate the molar mass of CH3SH:
The molar mass of carbon (C) is 12.01 g/mol, the molar mass of hydrogen (H) is 1.01 g/mol, and the molar mass of sulfur (S) is 32.07 g/mol. The molar mass of methanethiol (CH3SH) can be calculated as follows:
(1 × molar mass of C) + (4 × molar mass of H) + molar mass of S
= (1 × 12.01 g/mol) + (4 × 1.01 g/mol) + 32.07 g/mol
= 12.01 g/mol + 4.04 g/mol + 32.07 g/mol
= 48.12 g/mol
Step 2: Calculate the number of moles of CH3SH:
To calculate the number of moles, we divide the given mass (1.59 g) by the molar mass of CH3SH:
moles of CH3SH = mass of CH3SH / molar mass of CH3SH
= 1.59 g / 48.12 g/mol
≈ 0.033 moles
Step 3: Calculate the number of moles of SO2 formed:
From the balanced equation, we know that for every 2 moles of CH3SH combusted, 2 moles of SO2 are formed. Therefore, the number of moles of SO2 formed would also be 0.033 moles.
Step 4: Calculate the mass of SO2 formed:
Finally, we can calculate the mass of SO2 formed by multiplying the number of moles of SO2 formed by its molar mass:
mass of SO2 = moles of SO2 × molar mass of SO2
= 0.033 moles × (32.07 g/mol)
≈ 1.06 g
Therefore, approximately 1.06 grams of SO2 would be formed upon the complete combustion of 1.59 grams of methanethiol.