calculus

find the rms value of the function
i=15(1-e^-1/2t) from t=0 to t=4

asked by Alan
  1. If we let r = rms of f(t), then

    4r^2 = Int(15 - 15e^-1/2t)[0,4]
    = 15t + 30e^(-t/2)[0,4]
    = [60 + 30/e^2] - [0 + 30]
    = 60 + 30/e^2 - 30
    = 30 + 30/e^2
    =34.06

    so, r = 2.92

    see wikipedia on root mean square

    posted by Steve

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