what is oxidation state of NO2
The molecule, NO2, is zero as is all compounds. N in NO2 is +4 and O in NO2 is -2 each.
so....can u explain to me why NO3- the N is five?
NO3^-.
O is -2 each; there are 3 of them for -6 total. N must be +5 to leave a -1 charge on the ion [+5 +(-6) = -1]
To determine the oxidation state of NO2, we need to consider the individual oxidation states of nitrogen (N) and oxygen (O) atoms in the molecule.
Oxygen typically has an oxidation state of -2, unless it is bonded to a more electronegative element such as fluorine or in certain compounds where it has a positive oxidation state.
Let's assign the oxidation state of O as -2. Since there are two oxygen atoms in NO2, the total oxidation state contribution from oxygen is -2 * 2 = -4.
The sum of the oxidation states of all atoms in a neutral molecule is equal to zero. Since NO2 is neutral (no charge is given), the oxidation state of nitrogen (N) must be such that it balances out the oxidation state contribution from oxygen.
Let's represent the oxidation state of nitrogen as x.
Now, we can use the equation:
(-4) + x = 0
Solving this equation, we find that x = +4.
Therefore, the oxidation state of nitrogen (N) in NO2 is +4.