A car accelerates uniformly from rest to a speed of 72.7 km/h (20.2m/s) in 11 second. the distance the car travels during this time.

To calculate the distance the car travels during this time, we can use the formula for distance travelled during uniform acceleration:

d = (1/2) * a * t^2

Where:
d = distance travelled
a = acceleration
t = time taken

Given:
Initial velocity (u) = 0 m/s (as the car starts from rest)
Final velocity (v) = 20.2 m/s
Time (t) = 11 s

To find the acceleration (a), we can use the formula for uniform acceleration:

a = (v - u) / t

Plugging in the values, we have:

a = (20.2 m/s - 0 m/s) / 11 s
a = 20.2 m/s / 11 s
a ≈ 1.836 m/s^2

Now, we can substitute the values of acceleration and time into the formula for distance:

d = (1/2) * a * t^2
d = (1/2) * 1.836 m/s^2 * (11 s)^2
d = 0.5 * 1.836 m/s^2 * 121 s^2
d = 111.858 m

Therefore, the distance the car travels during this time is approximately 111.858 meters.