Write a net ionic equation for the overall reaction that occurs when aqueous solutions of hydrosulfuric acid and potassium hydroxide are combined. Assume excess base.
I omitted a coefficient in the overall equation. Also I didn't include aq for each. BUT do you realize you can have an OVERALL ionic equation OR you can have a net ionic equation but you can't have both in the same equation except in a few circumstances.
H2S + 2K^+ + 2OH^- =>2H2O + 2K^+ + S^2- is the overall ionic equation. The net ionic equation is
H2S(aq) + 2OH^&-(aq) ==> 2H2O(l) + S^2-(aq)
H2S(aq) + 2KOH(aq) ==> 2H2O(l) + K2S(aq)
H2S + 2K^+ + OH^- =>2H2O + 2K^+ + S^2-
Cancel the 2K^+
The net ionic equation is what remains.
A reaction occurs when aqueous solutions of hydrosulfuric acid and sodium hydroxide are combined.
This is correct
I would love to help you with that, but first, let me answer with a bit of humor:
Why did the acid and the base break up? Because they couldn't find the right pH balance!
Now, let's get to the net ionic equation, shall we?
First, let's write the balanced equation for the reaction:
H2SO4 (aq) + 2KOH (aq) → K2SO4 (aq) + 2H2O (l)
Next, we will separate the aqueous solutions into their respective ions:
H+ (aq) + SO4^2- (aq) + 2K+ (aq) + 2OH- (aq) → 2K+ (aq) + SO4^2- (aq) + 2H2O (l)
As you can see, the K+ and SO4^2- ions appear on both sides of the equation, so they cancel out. And that leaves us with the net ionic equation:
2H+ (aq) + 2OH- (aq) → 2H2O (l)
Voila! We have the net ionic equation, which shows the essential species involved in the reaction.
To write a net ionic equation, we first need to write the balanced chemical equation for the overall reaction. The given reactants are hydrosulfuric acid (H2S) and potassium hydroxide (KOH).
The balanced chemical equation for the reaction between H2S and KOH is:
H2S + 2KOH -> K2S + 2H2O
This equation shows the reactants on the left side and the products on the right side. However, to determine the net ionic equation, we need to identify the species that dissociate or ionize in the solution.
In this case, H2S is a weak acid, so it partially dissociates into its ions:
H2S (aq) -> 2H+ (aq) + S2- (aq)
KOH is a strong base and completely dissociates into its ions:
KOH (aq) -> K+ (aq) + OH- (aq)
Now, we can write the net ionic equation by removing the spectator ions. Spectator ions are the ions that appear on both sides of the equation and do not participate in the actual reaction.
The net ionic equation for the reaction between H2S and KOH would be:
H+ (aq) + OH- (aq) -> H2O (l)
This equation represents the ions that are actually involved in the reaction. H+ ion from H2S combines with OH- ion from KOH to form water (H2O).
Therefore, the net ionic equation for the reaction between hydrosulfuric acid and potassium hydroxide is:
H+ (aq) + OH- (aq) -> H2O (l)