my 10 digit is 4 times my 100 digit. who am I?
need more information
any number of the form
...xxxxxxx14x
...xxxxxxx28x
will work, where x is any digit, and there are as many digits to left as you want.
To determine the number described, we need to understand the structure of a multi-digit number. In a base-10 number system, each digit's position represents a multiple of a power of 10.
Let's break down the digits in a 10-digit number:
- The rightmost digit, also known as the units digit, represents the number of ones.
- The second-rightmost digit represents the number of tens.
- The third-rightmost digit represents the number of hundreds.
- And so on...
According to the given information, the 10-digit is four times the 100-digit. To represent this mathematically, let's assign variables to each digit of the number:
- Let 'x' represent the 10-digit.
- Let 'y' represent the 100-digit.
Based on the given condition, we can write the equation:
x = 4y
Since the 10-digit is four times the 100-digit, we can find potential values for 'x' and 'y' by substituting different values for 'y' and solving for 'x'. However, it's essential to remember that the number should have 10 digits, which means 'y' cannot be zero.
By trying out different values, we find that when 'y' is 2, we get 'x' as 8, satisfying the equation:
x = 4 * y
x = 4 * 2
x = 8
Therefore, the number described is 82,000,000. Note that all the digits after the 100-digit are zeros.
Actually, it occurs to me that
...xxxxxxx00x
also works