On october 9,1992, a 27 pound meteorite struck a car in peeskill,NY leaving a dent 22 cm deep on the trunk. If the meteorite struck the car with a speed of 550 m/s, what was the magnitude of its deceleration, assuming it to be content?

To calculate the magnitude of the deceleration of the meteorite, we need to use the formulas of motion and apply the concept of deceleration.

First, let's calculate the time it took for the meteorite to come to rest. We can use the formula:

v^2 = u^2 + 2as

where:
- v is the final velocity (0 m/s, since it comes to rest),
- u is the initial velocity (550 m/s),
- a is the deceleration (unknown),
- s is the displacement (22 cm = 0.22 m).

Rearranging the formula, we have:

a = (v^2 - u^2) / (2s)

a = (0 - (550^2)) / (2 * 0.22)

a = (-302,500) / 0.44

a ≈ -688,636.36 m/s^2

The magnitude of deceleration is the absolute value of the negative acceleration, so we have:

Magnitude of deceleration = |-688,636.36| m/s^2

Magnitude of deceleration ≈ 688,636.36 m/s^2

Therefore, the magnitude of the deceleration of the meteorite is approximately 688,636.36 m/s^2.