A 29 kg chair initially at rest on a horizontal
floor requires a 375 N horizontal force to set
it in motion. Once the chair is in motion, a
345 N horizontal force keeps it moving at a
constant velocity.
The acceleration of gravity is 9.81 m/s2 .
a) What is the coefficient of static friction
between the chair and the floor?
375=mu*mg
To find the coefficient of static friction between the chair and the floor, we can start by using the given information.
First, let's find the force required to set the chair in motion. It is given that a 375 N horizontal force is required to do so. This force is equal and opposite to the force of static friction acting on the chair.
Therefore, the force of static friction (Fs) is 375 N.
Next, let's calculate the weight of the chair, which is the force due to gravity acting on it. The weight (W) is equal to the mass (m) of the chair multiplied by the acceleration due to gravity (g).
Weight (W) = mass (m) × acceleration due to gravity (g)
W = 29 kg × 9.81 m/s²
W = 284.49 N
Now, using the concept of static friction, we know that the force of static friction (Fs) can be calculated as the product of the coefficient of static friction (μs) and the normal force (N).
Fs = μs × N
In this case, the normal force (N) is equal to the weight (W).
So, we can rewrite the equation as:
375 N = μs × 284.49 N
From this equation, we can solve for the coefficient of static friction (μs):
μs = 375 N / 284.49 N
μs ≈ 1.317
Therefore, the coefficient of static friction between the chair and the floor is approximately 1.317.