-2/3.[-4/5]=
-6-7=
A hospital parking lot charges $3.00 for the first hour or part thereof and $1.50 for each additional hour or part thereof. a weekly pass cost $33.00 and allows unlimited parking for 7 days. If each visit Johny makes to the hospital last three hours and a half hours, what is the minimum nubler of visits for which buying a pass would be less expensive than paying each time?
____visits would make it less expensive for Johny to buy a weekly pass.
For the first plan, the amount per week would 3+2.5(1.5) = 6.75 per day.
6.75x > 33
x > 33/6.75
x > 5
To solve the first equation -2/3 * -4/5, we need to multiply the two fractions together. Here's how you can do it step by step:
Explanation:
Step 1: Multiply the numerators (top numbers) of the two fractions together to get the new numerator. (-2) * (-4) = 8.
Step 2: Multiply the denominators (bottom numbers) of the two fractions together to get the new denominator. (3) * (5) = 15.
Step 3: Write down the new numerator over the new denominator to get the result. So, the answer is 8/15.
Now let's solve the second equation -6 - 7:
Explanation:
The negative sign in front of the 6 indicates that it is a negative number. When we subtract a positive number (7) from a negative number (-6), we remember that subtracting a positive number is the same as adding its negative. So, -6 - 7 can be rewritten as -6 + (-7).
Step 1: Add the negative values. -6 + (-7) = -13.
The result of -6 - 7 is -13.
Finally, let's calculate the minimum number of visits for which buying a weekly pass would be less expensive than paying each time.
Explanation:
Given:
Cost for the first hour or part thereof = $3.00
Cost for each additional hour or part thereof = $1.50
Cost of weekly pass = $33.00
To determine the minimum number of visits, we need to compare the cost of paying each time with the cost of buying a weekly pass.
If Johny pays each time, he will be charged $3.00 for the first three and a half hours. Since each visit lasts for three and a half hours, this means the cost for each visit is $3.00.
To find the minimum number of visits, we need to calculate when the sum of paying each time equals or exceeds the cost of the weekly pass ($33.00).
Cost of paying each time for n visits = $3.00 * n
Cost of weekly pass = $33.00
In equation form: $3.00 * n ≥ $33.00
To find the minimum number of visits for which buying a weekly pass would be less expensive, we solve the inequality by dividing both sides by $3.00:
n ≥ $33.00 / $3.00
n ≥ 11
Therefore, Johnny would need to make at least 11 visits for buying a weekly pass to be less expensive than paying each time.
So, the minimum number of visits for which buying a weekly pass would be less expensive for Johny is 11 visits.