Find two consecutive whole numbers such that 3/4 of the first number is 5 more than the second number.

let the first no. be X

let the second no. be X+1

(3/4)X= X+1+5

Then solve for X to get the answer

To solve this problem, we can break it down into steps:

Step 1: Let's represent the first whole number as x.

Step 2: The second consecutive whole number is one more than x, so we can represent it as (x + 1).

Step 3: According to the problem statement, 3/4 of the first number (3/4 * x) is 5 more than the second number ((x + 1) + 5).

Step 4: Now we can set up an equation to solve for x:
3/4 * x = (x + 1) + 5

Step 5: Simplify the equation:
3/4 * x = x + 6

Step 6: Multiply both sides of the equation by 4 to eliminate the fraction:
4 * (3/4 * x) = 4 * (x + 6)
3x = 4x + 24

Step 7: Subtract 4x from both sides of the equation:
3x - 4x = 24
-x = 24

Step 8: Multiply both sides of the equation by -1 to isolate x:
-1 * (-x) = -1 * 24
x = -24

Step 9: Since we are looking for consecutive whole numbers, we need to find x + 1:
-24 + 1 = -23

Therefore, the two consecutive whole numbers that satisfy the given conditions are -24 and -23.