calculate the numbers of moles of sodium thiosulfate (Na2S2O3) and hence the moles of S2O3^2- ions present in the volume of 43mL
someone plz help
You didn't provide enough information to answer but what you want is moles = M x L = M x 0.043L = ?
what does M means?
moles = molarity x liters (or molarity x litres if you're in the UK).
calculate the number of moles of I2 librated
To calculate the number of moles of sodium thiosulfate (Na2S2O3) and the moles of S2O3^2- ions in a given volume, you need to know the concentration of the solution.
Let's assume that you have a solution with a known concentration, expressed in moles per liter (mol/L) or molarity (M).
To find the moles of Na2S2O3:
1. Start by determining the concentration in moles per milliliter (mol/mL) by dividing the concentration in moles per liter (M) by 1000.
For example, if the concentration is 0.5 M, the concentration in mol/mL would be 0.5 mol/L ÷ 1000 = 0.0005 mol/mL.
2. Calculate the moles of Na2S2O3 by multiplying the concentration in mol/mL by the volume in milliliters (mL).
For a volume of 43 mL and a concentration of 0.0005 mol/mL:
moles of Na2S2O3 = 0.0005 mol/mL × 43 mL = 0.0215 mol.
To calculate the moles of S2O3^2- ions:
Since each Na2S2O3 molecule contains one S2O3^2- ion, the moles of S2O3^2- ions will be the same as the moles of Na2S2O3, which is 0.0215 mol in this case.
Therefore, in a volume of 43 mL with a concentration of 0.5 M, the number of moles of Na2S2O3 and S2O3^2- ions present would be 0.0215 mol.