Had The Same Teacher For Physics And Ughh I Am Stuck. Notes Help Me A Lot So If Anyone Could Write A Few Or A Bunch Out That Would Be Awesome. I Am Not The Type Of A Person Who Minds Writing Down Notes;)
Teacher Told Us About Work And That The Formula For It Is W = Fd. IS It?
Then We Also Got Told About Power. And Formula For That Is. W/t. W is Fd So Have To Do More Work Here To Get The Answer.
I Also Managed To Do Some Questions But Want To Make Sure I Did Them Right.
A force of 825 N is needed to push a car across a lot. Two students push the car 35m.
A. How much work is done?
B. After a rainstorm, the force needed to push the car doubled because the ground became soft. By what amount does the work done by the students change?
A. 28875J
B. 57750J
A delivery clerk carries a 34-N package from the ground to the fifth floor of an office building, a total height of 15m. How much work is done by the clerk?
Would it be zero??
What work is done by a fork life raising a 583-kg box 1.2m?
W = fd
W = (5719)(1.2)
W = 6863J
And If You're Wondering How I Got The Force Well I Multiplied Mass By Gravity.
U And A Friend each carry identical boxes to a room one floor above you and down the hall. U choose to carry it first up the stairs, then down the hall. Your friend carries it down the hall, then up another stairwell? Who does more work?
I think they both do the same amount of work just during different times..
To verify the formulas and answers provided by your teacher, we'll walk through the calculations step by step.
First, let's confirm the formula for work. Work (W) is indeed calculated using the formula W = F × d, where F represents force and d represents distance. So, the formula is correct.
Now, let's tackle the questions you've mentioned:
1. A force of 825 N is needed to push a car 35 m. To find the work done (W), we use the formula W = F × d. Plugging in the values, we have W = 825 N × 35 m, which gives us W = 28,875 J (Joules).
2. After the rainstorm, the force needed to push the car doubled. To find the change in work done, we need to compare the work done before and after the storm. Before the storm, the work done was 28,875 J. After the storm, the force doubled, so the new force is 2 × 825 N = 1,650 N. The distance remains the same, so using the formula W = F × d, we have W = 1,650 N × 35 m, which gives us W = 57,750 J. The change in work is then 57,750 J - 28,875 J = 28,875 J.
3. For the delivery clerk lifting a package, the work done is determined using the same formula: W = F × d. In this case, the force (F) is 34 N, and the distance (d) is 15 m. Plugging in these values, we have W = 34 N × 15 m, which gives us W = 510 J (Joules). So the work done by the delivery clerk is 510 J.
4. In the case of a forklift raising a box, you correctly multiplied the mass (m) by gravity to find the force (F = m × g). The force (F) is given as 5719 N (derived from the mass of 583 kg multiplied by the acceleration due to gravity, 9.8 m/s^2). The distance (d) is given as 1.2 m. Using the formula W = F × d, we have W = 5719 N × 1.2 m, which gives us W = 6863 J (Joules). Therefore, the work done by the forklift is 6863 J.
5. Regarding the question about carrying boxes, you are correct. Both you and your friend do the same amount of work, but in different ways. The work done is proportional to the force exerted and the distance covered. The total work done in both scenarios is the same, regardless of the order in which you carry the box.
Remember, when evaluating work, it's important to consider the formulas and concepts discussed in class. If you have any additional questions or need further clarification, feel free to ask!
Here are the notes summarizing what you've mentioned:
1. Work (W) is defined as the product of force (F) and displacement (d). The formula for work is W = Fd.
2. Power is the rate at which work is done. The formula for power is P = W/t, where P is power, W is work, and t is time.
Now let's go through the questions you provided:
1. A force of 825 N is needed to push a car across a lot for a distance of 35 m.
a) To find the work done, we can use the formula W = Fd, so W = (825 N)(35 m) = 28,875 J.
b) After the rainstorm, the force needed to push the car doubled. The work done is directly proportional to the force exerted. Therefore, the work done by the students also doubles, resulting in a change of 28,875 J to 57,750 J.
2. The delivery clerk carries a 34 N package from the ground to the fifth floor, a height of 15 m. The work done by the clerk can be calculated using the formula W = Fd, where F is the force and d is the displacement. In this case, the force and displacement are in the same direction, so the work done is given by W = (34 N)(15 m) = 510 J.
3. The work done by a forklift raising a 583 kg box by a height of 1.2 m can be calculated using the formula W = Fd, where F is the force and d is the displacement. The force required to lift the box can be found by multiplying the mass (583 kg) by the acceleration due to gravity (9.8 m/s^2). Thus, F = (583 kg)(9.8 m/s^2) = 5,719 N. Substituting these values into the formula, we get W = (5,719 N)(1.2 m) = 6,863 J.
4. Both you and your friend are carrying identical boxes to a room, but with different paths.
The work done is given by W = Fd. The force (F) remains constant because you and your friend are carrying identical boxes. However, the displacement (d) differs based on the path taken. Since work is the product of force and displacement, the one who covers the longer distance (higher displacement) will do more work.
In conclusion, your understanding of the concepts seems to be mostly correct. Keep practicing and reviewing, and you'll continue to improve.