what is the final concentration of a solution if 100mL of water is added to a 25mL of 5.0 M NaCl?
5.0M x (25/125) = ?? and this assume that the volumes are additive. Otherwise the problem can't be solved.
To find the final concentration of the solution, we need to consider the total volume of the solution after adding water.
Step 1: Calculate the initial number of moles of NaCl.
To do this, we use the formula:
moles = concentration × volume (in liters)
Given:
Initial volume of NaCl solution = 25 mL = 0.025 L
Initial concentration of NaCl solution = 5.0 M
moles = 5.0 M × 0.025 L = 0.125 moles
Step 2: Determine the final volume of the solution.
After adding 100 mL of water, the total volume of the solution will be 25 mL + 100 mL = 125 mL = 0.125 L
Step 3: Calculate the final concentration of NaCl.
To find the final concentration, divide the number of moles of NaCl by the final volume of the solution:
final concentration = moles / volume (in liters)
final concentration = 0.125 moles / 0.125 L = 1.0 M
Therefore, the final concentration of the solution will be 1.0 M.