For the sequence an=6+5*(n-1),
its first term is__??__ ;
its second term is__??__ ;
its third term is__??__ ;
its fourth term is__??__ ;
its fifth term is__??_ ;
its common difference d= __??__ .
To find the first term of the sequence an=6+5*(n-1), we substitute n=1 into the equation.
First term (a1) = 6 + 5 * (1-1)
= 6 + 5 * 0
= 6 + 0
= 6
Therefore, the first term is 6.
Similarly, we can find the second term by substituting n=2 into the equation.
Second term (a2) = 6 + 5 * (2-1)
= 6 + 5 * 1
= 6 + 5
= 11
Therefore, the second term is 11.
Using the same process, we can find the third, fourth, and fifth terms.
Third term (a3) = 6 + 5 * (3-1)
= 6 + 5 * 2
= 6 + 10
= 16
Therefore, the third term is 16.
Fourth term (a4) = 6 + 5 * (4-1)
= 6 + 5 * 3
= 6 + 15
= 21
Therefore, the fourth term is 21.
Fifth term (a5) = 6 + 5 * (5-1)
= 6 + 5 * 4
= 6 + 20
= 26
Therefore, the fifth term is 26.
The common difference (d) in this sequence is the difference between consecutive terms, which is always 5 in this case.
So, the common difference (d) is 5.