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12. Determine if the following is a conjuction or disjunction. y + 4 < 1 or y + 2 > 8 (Points : 1) 13. State how you determined if the combination above was a conjunction or disjunction. (Points : 2) 14. Solve the problem. (Hint:
asked by kim on April 7, 2015 
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use truth table to verify: 1.Distributive law P conjunction ( q disjunction r )= ( p conjunction q ) disjunction ( p conjunction r) 2.Associative law ( p disjunction q) disjunction r = p disjunction ( p disjunction r ) ( p
asked by Noor on November 20, 2014 
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use truth table to verify: 1.Distributive law P conjunction ( q disjunction r )= ( p conjunction q ) disjunction ( p conjunction r) 2.Associative law ( p disjunction q) disjunction r = p disjunction ( p disjunction r ) ( p
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use truth table to verify: 1.Distributive law P conjunction ( q disjunction r )= ( p conjunction q ) disjunction ( p conjunction r) 2.Associative law ( p disjunction q) disjunction r = p disjunction ( p disjunction r ) ( p
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Steve I already asked you the question about the absolute value of 3x2=8 and absolute vale x+1=1....value of x...and your answer was does 0 or 2 satisfy both ....they dont...so is it no solution?
asked by Deborah on February 1, 2013 
Algebrahelp please
I already asked this question once about the absolute value of 3x2=8 and absolute vale x+1=1....value of x?...and the answer I received was does 0 or 2 satisfy both ....they dont...so is it no solution? Please help  I do not
asked by Deborah on February 1, 2013 
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Find the absolute maximum and absolute minimum values of the function f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals. Enter 1000 for any absolute extrema that does not exist. (A) Interval = [1,4] Absolute maximum =
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Calculus (pleas help!!!)
Find the absolute maximum and absolute minimum values of the function f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals. Enter 1000 for any absolute extrema that does not exist. (A) Interval = [1,4] Absolute maximum =
asked by Cady on April 5, 2011