Can someone please help me!!!!!!
Find th eequation of the line containing the point P and having the slope m. Write your answer in slope intercept form. Graph this line. P= (0,0) M = 0
Using the slope intercept form y = mx + b with m = 0 and b = 0 to get y = 0
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Thank you it is the answer I finally came up with thought I was doing something wrong.
Of course! I can help you with that.
To find the equation of a line, you need both the slope (m) and a point on the line (P). In this case, the slope (m) is given as 0, and the point (P) is (0,0).
The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
Since the slope (m) is 0, the equation becomes y = 0x + b, which simplifies to y = b.
To find the value of b, we need to substitute the coordinates of the point P (0,0) into the equation. So, we get 0 = b.
Therefore, the y-intercept (b) is 0.
Putting it all together, the equation of the line is y = 0x + 0, which simplifies to y = 0.
Now, let's graph this line. Since the equation is y = 0, it means that the line is a horizontal line passing through the point (0,0). This line will be on the x-axis, as the y-coordinate is always 0.
Therefore, the graph will just be a straight line along the x-axis.
I hope this helps!