How much water must be added to 20liter of 12molar base solution to makt it 8molar?
To determine the amount of water that needs to be added to a 20-liter, 12 molar base solution to make it 8 molar, we need to use the formula for dilution:
C1V1 = C2V2
where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
In this case, the initial concentration is 12 M (molar), and the final concentration is 8 M. The initial volume is 20 liters, and we need to find the final volume by adding water. Let's call the final volume V2.
So, the equation becomes:
12 M x 20 L = 8 M x V2
240 = 8V2
To solve for V2, we divide both sides of the equation by 8:
V2 = 240 / 8
V2 = 30 liters
Therefore, to make the 20-liter, 12 molar base solution into an 8 molar solution, 10 liters of water should be added.