How many grams of CO2 would be produced from the following reaction sequence?
HI + KHCO3 -> KI + H2CO3
H2CO3 -> H2O + CO2
if 20.0 ml of 1.00 M KHCO3 solution is mixed with 20.0 ml of 1.50 M HI solution.
20 mL x 1.00M KHCO3 = 20 millimoles.
20 mL x 1.50M HI = 30 mmoles.
This is a 1:1 reaction (1 mole HI reacts with 1 mole KHCO3); therefore, the limiting reagent is KHCO3. Thus 20 mmoles H2CO3 will be produced (0.020 moles) which will produce 0.020 moles CO2.
grams = moles x molar mass.
0.88 g CO2
To determine the number of grams of CO2 produced from the given reaction sequence, we need to calculate the amount of CO2 produced in moles, and then convert it to grams using the molar mass.
First, let's write out the balanced chemical equations for the reactions given:
1) HI + KHCO3 -> KI + H2CO3
2) H2CO3 -> H2O + CO2
From the first equation, we can see that 1 mole of KHCO3 reacts with 1 mole of HI to produce 1 mole of H2CO3. Therefore, the number of moles of H2CO3 produced can be calculated using the stoichiometry of the reaction.
To calculate the moles of H2CO3:
1) Calculate the moles of KHCO3:
Moles of KHCO3 = Volume of KHCO3 solution (L) x Concentration of KHCO3 (mol/L)
= 0.020 L x 1.00 mol/L (1.00 M)
= 0.020 mol
2) Calculate the moles of HI:
Moles of HI = Volume of HI solution (L) x Concentration of HI (mol/L)
= 0.020 L x 1.50 mol/L (1.50 M)
= 0.030 mol
Since the stoichiometry of the reaction tells us that 1 mole of KHCO3 reacts with 1 mole of HI to produce 1 mole of H2CO3, the number of moles of H2CO3 produced is equal to the minimum of the two (0.020 mol).
Moving to the second equation, we see that 1 mole of H2CO3 decomposes to produce 1 mole of CO2. Therefore, the number of moles of CO2 produced is also equal to the number of moles of H2CO3.
Now that we know the number of moles of CO2 produced, we can calculate the mass of CO2 using its molar mass.
The molar mass of CO2 is calculated as follows:
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol (There are two oxygen atoms in CO2)
Molar mass of CO2 = (12.01 g/mol) + 2 * (16.00 g/mol) = 44.01 g/mol
Finally, to calculate the mass of CO2 produced:
Mass of CO2 = Moles of CO2 x Molar mass of CO2
= 0.020 mol x 44.01 g/mol
= 0.8802 g
Therefore, approximately 0.8802 grams of CO2 would be produced from the given reaction sequence.