Compared to a bicycle moving at 20 km/hr, how much momentum does the same bicycle have when moving at 60 km/hr?
To determine the momentum of an object, you need to know its mass and velocity. Momentum (p) is defined as the product of mass (m) and velocity (v), so mathematically it can be represented as: p = m * v.
To find the momentum of the bicycle moving at 60 km/hr compared to 20 km/hr, we need to assume that the mass of the bicycle remains constant. Therefore, the change in momentum will depend solely on the change in velocity.
Given that the bicycle's initial velocity (v1) is 20 km/hr and its final velocity (v2) is 60 km/hr, we can calculate the change in velocity (Δv) using the equation: Δv = v2 - v1.
In this case, Δv = 60 km/hr - 20 km/hr = 40 km/hr.
However, to make the units consistent, we need to convert km/hr to m/s. Since 1 km/hr equals 1000 m/3600 s, we can convert 40 km/hr to m/s as follows: Δv = (40 km/hr) * (1000 m/3600 s) = 11.11 m/s.
Now that we have the change in velocity (Δv), we can calculate the change in momentum (Δp) using the formula: Δp = m * Δv.
Since the mass (m) of the bicycle remains unchanged, we can disregard it in this calculation.
Therefore, the change in momentum (Δp) of the bicycle when its velocity increases from 20 km/hr to 60 km/hr is 11.11 m/s.