Consider the following reaction:

6A + 2B 5C + 4D
Determine the following rates at a time when the rate of consumption of B is 2.5E-05 M/s.
a) rate of consumption of A
M/s
b) rate of formation of C
M/s
c) rate of formation of D
M/s
d) rate of reaction
M/s

We must guess when you don't include an arrow. -->

a) 2.5E-5 x (6/2) =
etc.

So, for the rate of formation of C, would it be 2.5E-5 x (5/4)?

No, the coefficients are 5C and 2B, the fraction is 5/2.

To determine the rates of consumption of A, formation of C, formation of D, and the rate of the overall reaction at a time when the rate of consumption of B is given, we need to use the stoichiometry of the reaction.

In this reaction, we have the following stoichiometric coefficients:
A: 6
B: 2
C: 5
D: 4

Let's assume that the rate of consumption of B is given as 2.5E-05 M/s.

a) Rate of consumption of A:

Start with the stoichiometric ratio between A and B:
6A + 2B 5C + 4D

According to the stoichiometry, for every 2 moles of B consumed, 6 moles of A are also consumed. This means that the rate of consumption of A will be:
(6/2) * (2.5E-05 M/s) = 7.5E-05 M/s

So, the rate of consumption of A is 7.5E-05 M/s.

b) Rate of formation of C:

According to the stoichiometry, for every 2 moles of B consumed, 5 moles of C are formed. This means that the rate of formation of C will be:
(5/2) * (2.5E-05 M/s) = 6.25E-05 M/s

So, the rate of formation of C is 6.25E-05 M/s.

c) Rate of formation of D:

According to the stoichiometry, for every 2 moles of B consumed, 4 moles of D are formed. This means that the rate of formation of D will be:
(4/2) * (2.5E-05 M/s) = 5.0E-05 M/s

So, the rate of formation of D is 5.0E-05 M/s.

d) Rate of reaction:

Since the rate of reaction is the overall rate at which the reactants are consumed and products are formed, we can simply sum up the rates of consumption and formation to find the rate of reaction. In this case:
Rate of reaction = rate of consumption of A + rate of formation of C + rate of formation of D
= 7.5E-05 M/s + 6.25E-05 M/s + 5.0E-05 M/s
= 1.825E-04 M/s

So, the rate of reaction is 1.825E-04 M/s.