A hockey puck has a mass of 0.125 kg and is at rest. A hockey player makes a shot, exerting a constant force of 32.5 N on the puck for 0.16 s. With what speed does it head toward the goal?
6N
To find the speed at which the hockey puck heads toward the goal, we can use the equation:
Force = mass x acceleration
We know that the force exerted on the puck is 32.5 N, and the mass of the puck is 0.125 kg. We need to find the acceleration.
To find the acceleration, we can rearrange the equation:
acceleration = force / mass
Substituting the given values, we have:
acceleration = 32.5 N / 0.125 kg
acceleration ≈ 260 m/s^2
Now, we can use the equation:
velocity = acceleration x time
We know the acceleration is 260 m/s^2, and the time is 0.16 s. Substituting these values, we have:
velocity = 260 m/s^2 x 0.16 s
velocity ≈ 41.6 m/s
Therefore, the hockey puck heads toward the goal with a speed of approximately 41.6 m/s.
To determine the speed of the hockey puck, we can use the equation:
v = (F * t) / m
Where:
v = speed of the puck
F = force applied on the puck
t = time for which the force is applied
m = mass of the puck
In this case, the force applied on the puck is 32.5 N, the time for which the force is applied is 0.16 s, and the mass of the puck is 0.125 kg.
Plugging in these values into the equation, we get:
v = (32.5 N * 0.16 s) / 0.125 kg
To calculate this, we first multiply the force (32.5 N) by the time (0.16 s), which gives us 5.2 N·s. Then, we divide this by the mass of the puck (0.125 kg), resulting in:
v = 5.2 N·s / 0.125 kg
Now, we can simplify this equation:
v = 41.6 m/s
Therefore, the hockey puck will head toward the goal with a speed of 41.6 m/s.