Let a force of 1500 Newtons act through a distance of 200 meters on a 1500 kg car which starts from rest.
a. What is the work done?
b. What is the final velocity?
c. What is the car's momentum?
d. What is the car's change in momentum?
e. What is the car's Kinetic Energy?
f. What is the car's change in Kinetic Energy?
workdone=force*distanc
1/2 mv^2=work done solve for v
momentum=mv
changemomentum=mv-m*0
KE= workdone=1/2mv^2
change in KE= 1/2 mv^2-1/2 m*0^2
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. A car moving at 35 m/s on dry pavement, skids to a stop over 175 m. What is the coefficient of friction between the car’s tires and the pavement?
if 1000 kg car lifted through a distance of 0.50 m in 20 seconds what is the work done and the power spent in 20 seconds?
This is easy. Its E
To answer these questions, we need to use some basic physics formulas. Here are the step-by-step explanations for each question:
a. What is the work done?
Work is defined as the product of force and displacement. In this case, the force acting on the car is 1500 Newtons and the distance it moves is 200 meters. Therefore, the work done can be calculated using the formula:
Work = Force * Distance = 1500 N * 200 m = 300,000 Joules
So, the work done on the car is 300,000 Joules.
b. What is the final velocity?
To find the final velocity, we can use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy. The initial kinetic energy of the car is zero since it starts from rest.
The work done is 300,000 Joules, which is equal to the change in kinetic energy. So, we can set up the equation:
Work = Change in Kinetic Energy
300,000 J = (1/2) * mass * (final velocity)^2
The mass of the car is 1500 kg. Rearranging the equation, we get:
(final velocity)^2 = (2 * Work) / mass
(final velocity)^2 = (2 * 300,000 J) / 1500 kg
(final velocity)^2 = 400 m^2/s^2
Taking the square root, we find:
final velocity = √400 = 20 m/s
Therefore, the final velocity of the car is 20 m/s.
c. What is the car's momentum?
Momentum is defined as the product of an object's mass and its velocity. The mass of the car is 1500 kg, and the velocity we just found is 20 m/s.
Momentum = mass * velocity = 1500 kg * 20 m/s = 30,000 kg·m/s
So, the car's momentum is 30,000 kg·m/s.
d. What is the car's change in momentum?
The change in momentum can be found using the formula:
Change in Momentum = Final Momentum - Initial Momentum
Since the car starts from rest, the initial momentum is zero. The final momentum, as calculated in the previous question, is 30,000 kg·m/s.
Change in Momentum = 30,000 kg·m/s - 0 kg·m/s = 30,000 kg·m/s
So, the car's change in momentum is 30,000 kg·m/s.
e. What is the car's Kinetic Energy?
Kinetic energy is defined as one-half the mass times the square of the velocity. The mass of the car is 1500 kg, and the velocity we found earlier is 20 m/s.
Kinetic Energy = (1/2) * mass * (velocity)^2
Kinetic Energy = (1/2) * 1500 kg * (20 m/s)^2
Kinetic Energy = 600,000 Joules
Therefore, the car's kinetic energy is 600,000 Joules.
f. What is the car's change in Kinetic Energy?
Since the car starts from rest, the initial kinetic energy is zero. The change in kinetic energy is equal to the final kinetic energy, which we found in the previous question, since the initial kinetic energy is zero.
So, the car's change in kinetic energy is 600,000 Joules.