if 50.0 mLs of HCl of unknown concentration is titrated to neutrality with 90.0 mL of .650 M NaOH. calculate the molarity of the HCl
To calculate the molarity of the HCl solution, we need to use the concept of stoichiometry and the balanced chemical equation for the neutralization reaction between HCl and NaOH.
The balanced chemical equation for the reaction between HCl and NaOH is:
HCl + NaOH -> NaCl + H2O
From the balanced equation, we can see that the mole ratio between HCl and NaOH is 1:1. This means that 1 mole of HCl reacts with 1 mole of NaOH.
Step 1: Calculate the moles of NaOH used.
To calculate the moles of NaOH used, we first need to convert the volume of NaOH used from mL to L:
90.0 mL NaOH * (1 L / 1000 mL) = 0.0900 L NaOH
Now we can calculate the moles of NaOH used using its molarity:
moles NaOH = volume NaOH (L) * molarity NaOH (mol/L)
= 0.0900 L NaOH * 0.650 mol/L NaOH
= 0.0585 mol NaOH
Step 2: Use mole ratio to determine moles of HCl.
Since the mole ratio between HCl and NaOH is 1:1, the moles of HCl used is also 0.0585 mol.
Step 3: Use moles of HCl and volume of HCl to calculate its molarity.
We are given that the volume of HCl used is 50.0 mL, which is 0.0500 L:
molarity HCl = moles HCl / volume HCl (L)
= 0.0585 mol HCl / 0.0500 L HCl
= 1.17 M HCl
Therefore, the molarity of the HCl solution is 1.17 M.