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algebra

how do you perform this??

log x + log(x+3) = 1

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logarithms

  1. One of the main rules of logs is
    Log(AB) = Log A + Log B, as long as the base is the same

    so log x + log(x+3) = 1
    Log (x(x+3)) = 1
    Log(x^2 + 3x) = 1
    x^2 + 3x = 10^1
    x^2 + 3x - 10 = 0
    (x+5)(x-2) = 0

    x=-5 or x=2

    but in log x , x must be greater than 0
    so x = 2

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    Reiny

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