A closed-tube manometer is filled with a nmineal oil whose density is 0.857 g/cm^3. What is the pressure in mm Hg if you measure a height of the mineal oil equal to 79.3 mm? The density of mercury is given as 13.586 g/cm^3.
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To calculate the pressure using a closed-tube manometer, we need to consider the height of the fluid in the manometer and the density of the fluid.
In this case, the manometer is filled with a mineral oil, which has a density of 0.857 g/cm^3. The height of the mineral oil is given as 79.3 mm.
First, we need to convert the height from millimeters to centimeters by dividing it by 10:
Height of mineral oil = 79.3 mm / 10 = 7.93 cm
Next, we need to determine the pressure difference between the mineral oil and the reference fluid, which is mercury in this case. The density of mercury is given as 13.586 g/cm^3.
The pressure difference is given by the following formula:
Pressure difference = (density of the reference fluid - density of the mineral oil) * height of the mineral oil
Pressure difference = (13.586 g/cm^3 - 0.857 g/cm^3) * 7.93 cm
Now we can calculate the pressure using the pressure difference and the known density of the reference fluid. The unit of pressure in this case is millimeters of mercury (mm Hg), which is a commonly used unit for pressure measurements.
Pressure = Pressure difference / density of the reference fluid
Pressure = (13.586 g/cm^3 - 0.857 g/cm^3) * 7.93 cm / 13.586 g/cm^3
Finally, we can convert the pressure from g/cm^3 to mm Hg by multiplying it by the conversion factor: 1 mm Hg = 13.6 cm of mercury.
Pressure = Pressure * (1 mm Hg / 13.6 cm of mercury)
I'll calculate the pressure for you.