-3(x-4)<18 or 6-5x<-9
Didn't you see bobpursley's answer to your previous post??
http://www.jiskha.com/display.cgi?id=1321145300
-(x-4)<6
+(x-4)>-6
x > -2
or
-5 x < -15
-x < -3
+x > 3
so
x > -2 covers it
No, one is OR, the other is AND
The other one is to the right of X = 3 so that BOTH conditions are satisfied.
For only one OR the other condition to be satisfied, only being to the right of x=-2 is required.
They are matched trick questions :)
To solve the inequality -3(x-4)<18, we will follow these steps:
Step 1: Distribute -3 to the terms inside the parentheses:
-3 * x = -3x
-3 * -4 = 12
So, the inequality becomes: -3x + 12 < 18.
Step 2: To isolate x, subtract 12 from both sides of the inequality:
-3x + 12 - 12 < 18 - 12
-3x < 6.
Step 3: Divide both sides of the inequality by -3. Since we are dividing by a negative number, the inequality sign will reverse:
(-3x) / -3 > 6 / -3
x > -2.
Now, let's solve the second inequality: 6-5x<-9.
Step 1: Subtract 6 from both sides of the inequality:
(6 - 5x) - 6 < -9 - 6
-5x < -15.
Step 2: Divide both sides of the inequality by -5. Since we are dividing by a negative number, the inequality sign will reverse:
(-5x) / -5 > (-15) / -5
x > 3.
So, the solution to the inequalities is x > -2 or x > 3.